NCERT Class X Chapter 5: Arithmetic Progression Example 11
NCERT Class X Chapter 5: Arithmetic Progression Example 11 Question: Find the sum of the first 22 terms of the AP : 8, 3, –2, . . . Given: An Arithmetic Progression (AP) with first term a = 8, common difference d = 3 - 8 = -5, and number of terms n = 22. To Find: The sum of the first 22 terms of the AP, denoted by S 22 . Formula: The sum of the first n terms of an AP is given by the formula: S n = n 2 (2a + (n - 1)d) Solution: Given a = 8, d = -5, and n = 22. Substituting these values into the formula for S n : S 22 = 22 2 (2(8) + (22 - 1)(-5)) ⇒ S 22 = 11(16 + 21(-5)) ⇒ S 22 = 11(16 - 105) ⇒ S 22 = 11(-89) ⇒ S 22 = -770 Result: Therefore, the sum of the first 22 terms of the AP is -770. Next question solution: NCERT Class X Chapter 5: Arithmetic Progression Example 12 Explore more in Arithmetic Progressions chapter: Click this link to explore more NCERT Class X Chapter 5 Arithmetic Progressions solutions Exp...