NCERT Class X Chapter 7: Coordinate Geometry Example 7
NCERT Class X Chapter 7: Coordinate Geometry Example 7 Question: In what ratio does the point (–4, 6) divide the line segment joining the points A(–6, 10) and B(3, –8)? Given: A = (–6, 10), B = (3, –8), and P = (–4, 6) divides AB. To Find: The ratio in which the point P divides the line segment AB. Formula: Section formula: If a point \( P(x, y) \) divides the line segment joining \( A(x_1, y_1) \) and \( B(x_2, y_2) \) in the ratio \( m:n \), then \[ x = \frac{mx_2 + nx_1}{m + n}, \quad y = \frac{my_2 + ny_1}{m + n} \] Solution: Step 1: Let the required ratio be \( m:n \). Using the section formula for the x-coordinate: \[ -4 = \frac{m \times 3 + n \times (-6)}{m + n} \] Step 2: Cross multiply and simplify the equation for x-coordinate. \[ -4(m + n) = 3m - 6n \] \[ -4m - 4n = 3m - 6n \] \[ -4m - 4n - 3m + 6n = 0 \] \[ -7m + 2n = 0 \] \[ 2n = 7m \] Step 3: Express the ratio \( \frac{m}{n} \) from the above equation. \[ 2n = 7m \implies \fr...