NCERT Class X Chapter 4: Quadratic Equation Exercise 4.1 Question 2 (ii)
NCERT Class X Chapter 4: Quadratic Equation Exercise 4.1 2 (ii)
Question:
Represent the following situations in the form of quadratic equations :The product of two consecutive positive integers is 306. We need to find the integers.
Given:
The product of two consecutive positive integers = 306.To Find:
Quadratic equation representing the situation to find the integers.Formula:
WKT, consecutive integers differ by 1.Solution:
Let the first positive integer be 'x'.
Since the integers are consecutive,
the next positive integer will be 'x + 1'.
Since the integers are consecutive,
the next positive integer will be 'x + 1'.
According to the given condition, their product is 306.
⇒ x × (x + 1) = 306
⇒ x2 + x = 306
⇒ x × (x + 1) = 306
⇒ x2 + x = 306
Rearrange the equation into the standard quadratic form ax2 + bx + c = 0:
⇒ x2 + x - 306 = 0
⇒ x2 + x - 306 = 0
Result:
The situation can be represented by the quadratic equation: x2 + x - 306 = 0.Next Question Solution:
NCERT Class X Chapter 4: Quadratic Equation Exercise 4.1 2 (iii).Explore more in Quadratic Equations chapter:
Click this link to explore more NCERT Class X Chapter 4 Quadratic Equations solutions
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