NCERT Class X Chapter 3: Pair of Linear Equations In Two Variables Example 5

NCERT Class X Chapter 3: Pair of Linear Equations In Two Variables Example 5

Question:

Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” Represent this situation algebraically and graphically by the method of substitution.

Given:

  • Let the present age of Aftab be \( x \) years.
  • Let the present age of his daughter be \( y \) years.
  • Seven years ago, Aftab's age was \( x - 7 \) years, daughter's age was \( y - 7 \) years.
  • Seven years ago, Aftab was seven times as old as his daughter: \( x - 7 = 7(y - 7) \).
  • Three years from now, Aftab's age will be \( x + 3 \) years, daughter's age will be \( y + 3 \) years.
  • Three years from now, Aftab will be three times as old as his daughter: \( x + 3 = 3(y + 3) \).

To Find:

  • The present ages of Aftab (\( x \)) and his daughter (\( y \)).
  • Algebraic representation of the situation.
  • Graphical representation by the method of substitution.

Formula:

  • Linear equations in two variables: \( ax + by = c \)
  • Method of substitution: Solve one equation for one variable and substitute in the other.

Solution:

Step 1: Form the equations based on the given conditions.

$$ \begin{align*} &\text{Seven years ago:} \\ &\quad x - 7 = 7(y - 7) \\ &\text{Three years from now:} \\ &\quad x + 3 = 3(y + 3) \end{align*} $$

Step 2: Simplify both equations to standard form.

$$ \begin{align*} x - 7 &= 7y - 49 \\ x - 7y &= -42 \quad \text{(Equation 1)} \\ \\ x + 3 &= 3y + 9 \\ x - 3y &= 6 \quad \text{(Equation 2)} \end{align*} $$

Step 3: Express \( x \) in terms of \( y \) using Equation 2.

$$ x - 3y = 6 \\ \Rightarrow x = 6 + 3y $$

Step 4: Substitute the value of \( x \) in Equation 1 and solve for \( y \).

$$ \begin{align*} x - 7y &= -42 \\ (6 + 3y) - 7y &= -42 \\ 6 + 3y - 7y &= -42 \\ 6 - 4y &= -42 \\ -4y &= -42 - 6 \\ -4y &= -48 \\ y &= \frac{-48}{-4} \\ y &= 12 \end{align*} $$

Step 5: Substitute \( y = 12 \) in the expression for \( x \) to find \( x \).

$$ x = 6 + 3y = 6 + 3 \times 12 = 6 + 36 = 42 $$

Step 6: State the solution.

  • Aftab's present age (\( x \)) = 42 years
  • Daughter's present age (\( y \)) = 12 years

Step 7: Represent the equations graphically.

Rewrite the equations in the form \( x = my + c \):

$$ \begin{align*} x - 7y &= -42 \implies x = 7y - 42 \\ x - 3y &= 6 \implies x = 3y + 6 \end{align*} $$

Choose values of \( y \) to get corresponding values of \( x \):

For \( x - 7y = -42 \):

\( y \)\( x \)
0-42
60
1242

For \( x - 3y = 6 \):

\( y \)\( x \)
06
624
1242

The two lines intersect at \( (42, 12) \), which is the solution.

Result:

  • Aftab's present age = 42 years
  • Daughter's present age = 12 years
  • Algebraic equations:
    • \( x - 7y = -42 \)
    • \( x - 3y = 6 \)
  • Graphically, the lines \( x - 7y = -42 \) and \( x - 3y = 6 \) intersect at \( (42, 12) \).
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