NCERT Class X Chapter 3: Pair of Linear Equations In Two Variables Example 5
NCERT Class X Chapter 3: Pair of Linear Equations In Two Variables Example 5
Question:
Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” Represent this situation algebraically and graphically by the method of substitution.
Given:
- Let the present age of Aftab be \( x \) years.
- Let the present age of his daughter be \( y \) years.
- Seven years ago, Aftab's age was \( x - 7 \) years, daughter's age was \( y - 7 \) years.
- Seven years ago, Aftab was seven times as old as his daughter: \( x - 7 = 7(y - 7) \).
- Three years from now, Aftab's age will be \( x + 3 \) years, daughter's age will be \( y + 3 \) years.
- Three years from now, Aftab will be three times as old as his daughter: \( x + 3 = 3(y + 3) \).
To Find:
- The present ages of Aftab (\( x \)) and his daughter (\( y \)).
- Algebraic representation of the situation.
- Graphical representation by the method of substitution.
Formula:
- Linear equations in two variables: \( ax + by = c \)
- Method of substitution: Solve one equation for one variable and substitute in the other.
Solution:
Step 1: Form the equations based on the given conditions.
$$ \begin{align*} &\text{Seven years ago:} \\ &\quad x - 7 = 7(y - 7) \\ &\text{Three years from now:} \\ &\quad x + 3 = 3(y + 3) \end{align*} $$Step 2: Simplify both equations to standard form.
$$ \begin{align*} x - 7 &= 7y - 49 \\ x - 7y &= -42 \quad \text{(Equation 1)} \\ \\ x + 3 &= 3y + 9 \\ x - 3y &= 6 \quad \text{(Equation 2)} \end{align*} $$Step 3: Express \( x \) in terms of \( y \) using Equation 2.
$$ x - 3y = 6 \\ \Rightarrow x = 6 + 3y $$Step 4: Substitute the value of \( x \) in Equation 1 and solve for \( y \).
$$ \begin{align*} x - 7y &= -42 \\ (6 + 3y) - 7y &= -42 \\ 6 + 3y - 7y &= -42 \\ 6 - 4y &= -42 \\ -4y &= -42 - 6 \\ -4y &= -48 \\ y &= \frac{-48}{-4} \\ y &= 12 \end{align*} $$Step 5: Substitute \( y = 12 \) in the expression for \( x \) to find \( x \).
$$ x = 6 + 3y = 6 + 3 \times 12 = 6 + 36 = 42 $$Step 6: State the solution.
- Aftab's present age (\( x \)) = 42 years
- Daughter's present age (\( y \)) = 12 years
Step 7: Represent the equations graphically.
Rewrite the equations in the form \( x = my + c \):
$$ \begin{align*} x - 7y &= -42 \implies x = 7y - 42 \\ x - 3y &= 6 \implies x = 3y + 6 \end{align*} $$Choose values of \( y \) to get corresponding values of \( x \):
For \( x - 7y = -42 \):
| \( y \) | \( x \) |
|---|---|
| 0 | -42 |
| 6 | 0 |
| 12 | 42 |
For \( x - 3y = 6 \):
| \( y \) | \( x \) |
|---|---|
| 0 | 6 |
| 6 | 24 |
| 12 | 42 |
The two lines intersect at \( (42, 12) \), which is the solution.
Result:
- Aftab's present age = 42 years
- Daughter's present age = 12 years
- Algebraic equations:
- \( x - 7y = -42 \)
- \( x - 3y = 6 \)
- Graphically, the lines \( x - 7y = -42 \) and \( x - 3y = 6 \) intersect at \( (42, 12) \).
Next question solution:
NCERT Class X Chapter 3: Pair of Linear Equations In Two Variables Example 6Explore more in Pair of Linear Equations:
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