NCERT Class X Chapter 4: Quadratic Equation Exercise 4.3 Question 2 (i)
NCERT Class X Chapter 4: Quadratic Equation Exercise 4.3 2 (i)
Question:
Find the values of k for each of the following quadratic equations, so that they have two equal roots: 2x2 + kx + 3 = 0.
Given:
The quadratic equation: 2x2 + kx + 3 = 0To Find:
The value(s) of 'k' such that the equation has two equal roots.Formula:
For quadratic equation of the form ax2 + bx + c = 0 to have two equal roots, its discriminant (Δ) must be equal to zero.Δ = b2 - 4ac = 0
Solution:
The given quadratic equation is 2x2 + kx + 3 = 0.
Comparing it with the standard form ax2 + bx + c = 0, we have:
a = 2
b = k
c = 3
a = 2
b = k
c = 3
For two equal roots, the discriminant must be zero (Δ = 0):
⇒ b2 - 4ac = 0
⇒ (k)2 - 4(2)(3) = 0
⇒ k2 - 24 = 0
⇒ k2 = 24
⇒ k = ±√24
⇒ k = ±√(4 × 6)
⇒ k = ±2√6
⇒ b2 - 4ac = 0
⇒ (k)2 - 4(2)(3) = 0
⇒ k2 - 24 = 0
⇒ k2 = 24
⇒ k = ±√24
⇒ k = ±√(4 × 6)
⇒ k = ±2√6
Result:
The values of k for which the quadratic equation 2x2 + kx + 3 = 0 has two equal roots are k = 2√6 and k = -2√6.
Next Question Solution:
NCERT Class X Chapter 4: Quadratic Equation Exercise 4.3 Question 2 (ii).Explore more in Quadratic Equations chapter:
Click this link to explore more NCERT Class X Chapter 4 Quadratic Equations solutions
© Kaliyuga Ekalavya. All rights reserved.
Comments
Post a Comment