NCERT Class X Chapter 5: Arithmetic Progression Exercise 5.3 Question 1(i)

Question:

Find the sum of the following APs:2, 7, 12, . . ., to 10 terms.

Given:

An Arithmetic Progression (AP): 2, 7, 12, ... with 10 terms.

To Find:

The sum of the AP up to 10 terms.

Formula:

The sum of an AP is given by: S_n = n2(2a + (n - 1)d), where 

'n' is the number of terms, 

'a' is the first term, and 

'd' is the common difference.

Solution:

Here, a = 2, d = 7 - 2 = 5, and n = 10.

Substituting these values into the formula:

S₁₀ = 102(2(2) + (10 - 1)5) 

⇒ S₁₀ = 5(4 + 45) 

⇒ S₁₀ = 5(49) 

⇒ S₁₀ = 245

Result:

The sum of the AP up to 10 terms is 245.

Next question solution:

NCERT Class X Chapter 5: Arithmetic Progression Exercise 5.3 Question 1(ii)

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