NCERT Class X Chapter 14: Probability Exercise 14.1 Question (13)
NCERT Class X Chapter 14: Probability Exercise 14.1 Question 13
Question:
A die is thrown once. Find the probability of getting:
(i) a prime number;
(ii) a number lying between 2 and 6;
(iii) an odd number.
Given:
A die is thrown once. The sample space S = {1, 2, 3, 4, 5, 6}
To Find:
(i) Probability of getting a prime number.
(ii) Probability of getting a number between 2 and 6.
(iii) Probability of getting an odd number.
Formula:
Probability = Number of favorable outcomes Total number of outcomes
Solution:
(i) Prime numbers in S are {2, 3, 5}. Number of prime numbers = 3
Probability (prime number) = 3 6 = 1 2
(ii) Numbers between 2 and 6 are {3, 4, 5}. Number of such numbers = 3
Probability (number between 2 and 6) = 3 6 = 1 2
(iii) Odd numbers in S are {1, 3, 5}. Number of odd numbers = 3
Probability (odd number) = 3 6 = 1 2
Result:
(i) Probability of getting a prime number = 1 2
(ii) Probability of getting a number between 2 and 6 = 1 2
(iii) Probability of getting an odd number = 1 2
Comments
Post a Comment