NCERT Class X Chapter 14: Probability Exercise 14.1 Question (12)
NCERT Class X Chapter 14: Probability Exercise 14.1 Question 12
Question:
A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Fig. 14.5), and these are equally likely outcomes. What is the probability that it will point at
(i) 8?
(ii) an odd number?
(iii) a number greater than 2?
(iv) a number less than 9?
Given:
Total number of outcomes = 8 (1, 2, 3, 4, 5, 6, 7, 8)
To Find:
(i) Probability of pointing at 8
(ii) Probability of pointing at an odd number
(iii) Probability of pointing at a number greater than 2
(iv) Probability of pointing at a number less than 9
Formula:
Probability = Number of favorable outcomes Total number of outcomes
Solution:
(i) Probability of pointing at 8:
Number of favorable outcomes = 1 (only 8)
Total number of outcomes = 8
Probability =
1
8
(ii) Probability of pointing at an odd number:
Odd numbers are 1, 3, 5, 7
Number of favorable outcomes = 4
Total number of outcomes = 8
Probability =
4
8
=
1
2
(iii) Probability of pointing at a number greater than 2:
Numbers greater than 2 are 3, 4, 5, 6, 7, 8
Number of favorable outcomes = 6
Total number of outcomes = 8
Probability =
6
8
=
3
4
(iv) Probability of pointing at a number less than 9:
All numbers (1, 2, 3, 4, 5, 6, 7, 8) are less than 9.
Number of favorable outcomes = 8
Total number of outcomes = 8
Probability =
8
8
= 1
Result:
(i) Probability of pointing at 8 =
1
8
(ii) Probability of pointing at an odd number =
1
2
(iii) Probability of pointing at a number greater than 2 =
3
4
(iv) Probability of pointing at a number less than 9 = 1
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